I'm guessing it's my copiler (Dev C++), but I'm just going to ask. Let's say I have a malloc function, which allocates the amount of memory I want, and then returns a pointer to the beginning of that block.

 

However, when I try to malloc and return the adress to a char pointer, it gives me invalid conversion from void* to char*. I tried typecasting, but the ISO forbids it... any ideas?

1) Dev-C++ is not a compiler, just a GUI.

2) Don't use malloc, use new and delete (In case of using C++, and NOT C that is).

3) The way to assign a void* to char* goes like this (This is a copy/paste of a memcpy, me and some other guys have made for an OS project):

 

void* memcpy(void* dest, const void* src, size_t count)
{
void* ret = dest;

unsigned char* csrc = (unsigned char*)src;
unsigned char* cdest = (unsigned char*)dest;

while (count--)
{
	*cdest++ = *csrc++;
}
return cdest;
}

 

Note: This code is C, and I have not tried compiling it in C++.

1) Dev-C++ is not a compiler, just a GUI.

2) Don't use malloc, use new and delete (In case of using C++, and NOT C that is).

3) The way to assign a void* to char* goes like this (This is a copy/paste of a memcpy, me and some other guys have made for an OS project):

 

void* memcpy(void* dest, const void* src, size_t count)
{
void* ret = dest;

unsigned char* csrc = (unsigned char*)src;
unsigned char* cdest = (unsigned char*)dest;

while (count--)
{
	*cdest++ = *csrc++;
}
return cdest;
}

 

Note: This code is C, and I have not tried compiling it in C++.

 

Thanks. Actually, it turns out I was being retarded and typecasting on the wrong side of the equation (what the hell was I thinking?). Anyway, it works now... so yeah. Thanks anyway. And it's not actually malloc that I'm using, it's GlobalAlloc (thought I assume they're pretty much the same thing). But whatever. Thanks for the help anyway.